if there exists four arithmetic means between A and B ,and there exists another five arithemetic means between A and B if the sum of the five means exceeds the sum of the four means by 15.5 and if the first mean of the four means exceeds the first means of the five means by 0.5 then find A and B

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السلام عليكم
first sequence
A,A+C,A+2C,A+3C,A+4C,A+5C=B
SECOND
A,A+D,A+2D,A+3D,A+4D,A+5D,A+6D=B
THEN A+5C=A+6D THEN C=5/6 D............1
WE HAVE ( A+C)-(A+D)=0.5 THEN C-D=0.5.........2
THEN FROM 1 AND 2 C=3 AND D=2.5
FROM THE FIIREST GIVEN
5A+15D-4A-10C=15.5 SUBSITITUTE C AND D THEN
A=8 AND B=23

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