a slosed container of 2 litres volume contains 8 moles of nitrogen gas and 12 moles of oxygen gas react togather according to the equation : N2g +1/2 O2g N2O g and at equliberium the sum of moles of reactant and products is 17 moles :
a- calculate the number of moles of each gas at equliberium
b - calculate the equlibrium constamt Kc of the reaction

ليه مفيش حد بيرد على هذا السؤال

correct equation N2+2O2-----=2NO2
here is excess N2 in the rx so there is only 6 moles reacting
and 2 moles excess1
15=the total reacting moles =17-2(the excess
Now the sum of moles of the equation 5x=15 x=3
The eq now is 3N2+6O2------=6NO2

بعد كده تحسب التركيز و تستخدم قانون الkc

thank u..................

number of moles at equilibrium ,nitrogen =2
oxygen =9
di nitrogen oxide = 6
so the kc= 1.414
best regards
Saif Soliman
saif.soliman@stemegypt.edu.eg

Dear colleague, you suppose the reaction is complete reaction and neglected its reversibility ,from this point you calculate the excess reagent and complete the problem . but the correct answer you can see it below with saif soliman and you can contact me to discuss this issue best regards