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ارجوكم حل هذه المسئلة
a slosed container of 2 litres volume contains 8 moles of nitrogen gas and 12 moles of oxygen gas react togather according to the equation : N2g +1/2 O2g N2O g and at equliberium the sum of moles of reactant and products is 17 moles : a- calculate the number of moles of each gas at equliberium |
ليه مفيش حد بيرد على هذا السؤال
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correct equation N2+2O2-----=2NO2
here is excess N2 in the rx so there is only 6 moles reacting and 2 moles excess1 15=the total reacting moles =17-2(the excess Now the sum of moles of the equation 5x=15 x=3 The eq now is 3N2+6O2------=6NO2 |
بعد كده تحسب التركيز و تستخدم قانون الkc
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thank u..................
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number of moles at equilibrium ,nitrogen =2
oxygen =9 di nitrogen oxide = 6 so the kc= 1.414 best regards Saif Soliman saif.soliman@stemegypt.edu.eg |
Dear colleague, you suppose the reaction is complete reaction and neglected its reversibility ,from this point you calculate the excess reagent and complete the problem . but the correct answer you can see it below with saif soliman and you can contact me to discuss this issue best regards
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