حل المسالة رقم 3
س ص = جاس جتا س
س ص = 5. جا 2س
ص+ س دص\دس =جتا 2س
دص\دس +دص\دس + س د2ص\دس2 = -2 جا 2س ندخل ال جا بعكس الاشاره
وبضرب 4 فى المعادلة الاصلية نجد ان 4س ص = 2جا2س
اذن س د2ص\دس2 + 2دص\دس +4س ص = صفر
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