وده كمان حل اخر للمسألة
(Req)1 = 2Rg / (2+Rg) +35
(Req)2 =3Rg / (3+Rg)+45
I1 = VB/(Req)1 = VB(2+Rg) / 35(2 +Rg)+2Rg
I2 = VB /(Req)2 = VB(3+Rg) / 45(3+Rg)+3Rg
I1(Req)1= I2(Req)2
[VB(2+Rg) / 35(2 +Rg)+2Rg ]* [2Rg /(2+Rg)] =
[VB(3+Rg) / 45(3+Rg)+3Rg]*[3Rg/(3+Rg)]
210+111Rg = 270+96Rg
15Rg =60
Rg = 4
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