the iron = 63.63
the sulpher = 36.47
(in the case of giving you the percent you can just delete the percentage symbol and complete your problem )
then divide the percent of the elemnt on it's atomich mass therefor =
iron = 63.63\558 = 0.114
sulpher = 36.47 \32 = 1.13
the two numbers resulted from the dividing of the percent of element on it's atomich mass is your number of moles
then you get the smaller result which is the (0.114)
and divide the both results on it and you will get the ratio of moles which is
0.114 \ 0.114 = 1
1.13 \ 0.114 = 9
so the empirical formula is FeS9
you can chech that with your teacher
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