الكرة اللي غاصت :
Ft = Fg – ρ V g
5000 – 1000 × .3 × 10=
=2000
الكرة اللي طفت :
Ft = ρ V g - Fg
=1000 × .3 × 10 – (.5 × 1000)
=2500
وحجم الجزء المغمور
Fg = ρ V̀ g
.5 × 1000 = 1000 × V̀ × 9.8
V̀ = .051
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