ABCD is trapezium , where AD \\ BC
X is mid-point of AB
Prove that:
Area [⍙YXC] =½h x XY …….1
Area [⍙YXD] =½h x XY …….2
by adding
Area [⍙YXD] + Area [⍙YXC] =½h x XY + ½ h x XY
Area [⍙CXD] =XY x h
=½ x 2 x h x XY where [2h] is the height of trapezium
= ½ Area ABCD
