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![]() ![]() and its tenth term = 21, how many terms starting from the first should be taken to make the sum = 440 ? when s1 + s3 = 10 then a + a+ 2r = 10 then 2a + 2 r = 10 then a +r = 5 and the tenth term = 21 then a + 9 r = 21 subtract the two equ then 8r = 16 then r = 2 and a = 3 thearithmetic sequence is ( 3 ,5, 7 , ....................... ) |
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