Here the questions on Trigonometry in Img file.

[my shabana]

المشاركة الأصلية كتبت بواسطة احمد عبدالعال محمد

ok , and here is the 1st.,2nd. & 3rd. question answers
Ahmed

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بسم الله الرحمن الرحيم
A+B+C= 180
(SO 3l2(A+B+C)=3l2(180
( THEN 3l2(A+B=(270-3l2C
i.e TAN(3l2 A+3l2B=TAN(270-3l2C) = COT(3l2C) =1l (TAN3l2C
i.e ( tan3l2a+3l2b)÷(1-tan3l2a.tan3l2b)=1÷tan3l2c

tan3l2a.tan3l2c+tan3l2b.tan3l2c=1-tan3l2a.tan3l2b
i.e tan3l2a.tan3l2c+tan3l2b.tan3l2c+tan3l2a.tan3l2b=1

with my best wishes to my prof.mr.AHMEB

shabana